NetBurner Community Forum

I’m Sorry…. I thought the Netburner people were involved here…

Hey guys please, I'm stuck on this, I need the schematic….

I'm seting the TSTRIP5 port for CAN use. I have some doubts when it comes to connect these optional jumpers: JP3 HSR (High slew rate) JP21 GND JP21 PIN (Power IN) 1) when JP21 is present at 2-3, is the TSTRIP5 pin 1 GND identical to pin 3 GND? 2) the HSR jumper sure is related to the pin RS of the 8...

Thanks again Larry; yours is the kind of answer I was looking for.

Pat

rnixon wrote:I've used the Mod5234, which has the same processor as the CB34EX, and it works great.

you know that works but you do not why... that's ok for some people....

Once the CAN RX buffer is locked the serial receive buffer can still receive another packet but it will wait to transfer it to the RX buffer until it is unlocked. This is basically a 2 buffer hardware fifo. If a third packet is sent while the RX buffer is locked and there is a packet in the serial ...

Its not 8 times performance, and it only works if the processor can catch up, which may not happen if you have a sustained full load. OMG, you haven’t brought a single figure but you are denying mines… On a Netburner platform I have 61 uS to retrieve a CAN packet on a SJA1000 I have EIGHT times 61 ...

Here are the rough latency calculations from a benchmark application I posted to the group. The interrupt latency on any product with a 70 or 34 processor is about 4.59uS if SRAM is not enabled. By default SRAM is enabled and the interrupt latency is 0.83uS. If the task stack that is current is not...

Even if you have a h/w buffer, if you have an overrun issue there is always the possibility it could be sustained long enough to have a problem as well. I would not consider it a robust system to rely on a 64 byte fifo in h/w, rather than a overall system design with low latency to keep up in the f...

considering CAN 2.0b dataframes (and disregarding bit stuffing) the smallest dataframe is 1+29+6+0+16+2+7= 61 bits The biggest dataframe is 1+29+6+8*8+16+2+7= 125 bits Considering a 1Mb/s bus the smallest dataframe takes on the bus => 61 uS The biggest dataframe takes on the bus=> 125 uS That tells ...